Reflections using vectors (HL)

Reflecting point PP across a line or a plane, and some extensions that are probably beyond the syllabus. It’s more important to visualize the steps and draw a diagram, rather than memorizing them.

To find the reflection point RR, often we need to find the nearest point QQ on the line or plane.

Then utilize the midpoint formula.

Last edited: 2026-06-09 added diagrams and made the solutions more consistent

Contents

Reflect point across a point

The reflection of point PP across point QQ, is

OR=2OQOP=OP+2PQ\begin{align*} \overrightarrow{OR} &= 2\overrightarrow{OQ} - \overrightarrow{OP} \\ &= \overrightarrow{OP} + 2\overrightarrow{PQ} \end{align*}

meaning that PP and its reflection average to QQ, or that you start from the point then add twice of the displacement vector to QQ.

 	
OP + 2PQ = OR, where Q is the midpoint between P and R

Similarly to reflect a line or a plane across a point, reflect a point on the line or plane. The new line or plane has the same direction vector or normal vector as before, but passing through the reflected point.

Reflect point across a plane

Given some plane ax+by+cz=dax + by + cz = d, the line through PP perpendicular to the plane is

r=OP+λabc\bm r = \overrightarrow{OP} + \lambda \cvec abc

Solve for the λ0\lambda_0 at the point of intersection.

PP is at λ=0\lambda = 0, the intersection QQ is at λ=λ0\lambda = \lambda_0, and the reflected point is at λ=2λ0\lambda = 2\lambda_0.

OR=OP+2λ0abc\overrightarrow{OR} = \overrightarrow{OP} + 2\lambda_0 \cvec abc
 	
OP + 2λ<sub>0</sub>n = OR, where Q is the midpoint between P and R

Reflect a line across a parallel plane

Reflect the given point on the line, across the plane. The reflected line has the same direction vector as before but goes through the reflected point.

Similar ideas exist for reflecting a line across a parallel line, a plane across a parallel line, and a plane across a parallel plane.

Reflect a line across a non-parallel plane

Find the intersection.

Reflect the given point on the line, across the plane. The reflected line goes through the intersection and the reflected point.

Alternatively you can also reflect any two points on the line and find the line through those new points.

Reflect point across across a line

Finding the reflection across r=OA+λd\bm r = \overrightarrow{OA} + \lambda \bm d, given PA=OAOP\overrightarrow{PA} = \overrightarrow{OA} - \overrightarrow{OP}.

First find λ0\lambda_0 such that (PA+λ0d)d=0\left(\overrightarrow{PA} + \lambda_0 \bm d\right) \cdot \bm d = 0, where λ0d\lambda_0 \bm d is a vector from PP to the nearest point QQ, and the vector sum is perpendicular to the line.

The point on the line nearest to OP\overrightarrow{OP} is

OQ=OA+λ0d\overrightarrow{OQ} = \overrightarrow{OA} + \lambda_0 \bm d

As the point and its reflection average to OR\overrightarrow{OR}, the reflected point is

OR=2OQOP=2(OA+λ0d)OP=OP+2PQ=OP+2(PA+λ0d)\begin{align*} \overrightarrow{OR} &= 2\overrightarrow{OQ} - \overrightarrow{OP} \\ &= 2\left(\overrightarrow{OA} + \lambda_0 \bm d\right) - \overrightarrow{OP} \\ &= \overrightarrow{OP} + 2\overrightarrow{PQ} \\ &= \overrightarrow{OP} + 2\left(\overrightarrow{PA} + \lambda_0 \bm d\right) \\ \end{align*}
 	
OP + 2(PA+λ<sub>0</sub>d) = OR, where Q is the midpoint between P and R

You can also reflect lines and planes across a (non-parallel) line, but they get tedious. One way is finding the equations of the line (or plane) from the reflections of two (or three) points.