Right triangle trigonometry

The entirety of trigonometry is based on similarity and right triangles.

Contents

Trigonometric ratios

Hypotenuse is longest side in right triangle; opposite and adjacent are in relation to the angle in question
Hypotenuse, opposite and adjacent in relation to an acute angle in a right triangle

For an acute angle θ\theta in a right triangle, we define

sinθ=oppositehypotenuse\sin\theta = \frac{\text{opposite}}{\text{hypotenuse}}
cosθ=adjacenthypotenuse\cos\theta = \frac{\text{adjacent}}{\text{hypotenuse}}
tanθ=oppositeadjacent\tan\theta = \frac{\text{opposite}}{\text{adjacent}}

as ratios of side lengths in a right triangle.

For similar triangles, sinθ\sin\theta, cosθ\cos\theta, and tanθ\tan\theta remain the same, despite changes in side lengths. In other words, the trigonometric ratios only depend on the angle, so they are also called trigonometric functions.

In right triangles, trig ratios are useful when you need to find a missing side.

To find the angle, use the arcsin\arcsin, arccos\arccos, and arctan\arctan functions of the ratio of the sides.

Example: Using a diagram or otherwise, simplify

arctan1+cosθsinθ,0<θπ2\arctan\frac{1+\cos\theta}{\sin\theta},\,0 < \theta \leq \frac\pi2

From the Pythagorean identity, we have

sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1

which corresponds to a right triangle ABC{ABC} with θ=AC^B{\theta = A\hat{C}B} and legs AB=sinθ{AB = \sin\theta}, BC=cosθ{BC = \cos\theta}, and hypotenuse AC=1AC = 1. 1+cosθ{1+\cos\theta} can be interpreted as the base of a larger triangle ABDABD while keeping the height of sinθ\sin\theta. Here is a diagram.

Initial diagram showing angle theta
Initial diagram showing right triangle ABC inside right triangle ABD

From sum of angles in triangle ABCABC, we have BA^C=90°θ.B\hat{A}C = 90\degree - \theta.

From supplementary angles and sum of angles in triangle ACDACD, we have θ=CA^D+CD^A\theta = C\hat{A}D + C\hat{D}A

Since AC=AD=1AC = AD = 1, triangle ACDACD is isosceles, meaning the two remaining angles are equal and must be θ2\frac{\theta}{2}. Here is a diagram with all the new information as well.

Final diagram with all angles labelled in terms of theta
Final diagram with all angles labelled in terms of theta

Then by definition of tan\tan, the desired angle is BA^DB\hat{A}D with opposite side 1+cosθ1 + \cos \theta and adjacent sinθ\sin\theta.

arctan1+cosθsinθ=90°θ+θ2=90°θ2\begin{align*} \arctan\frac{1+\cos\theta}{\sin\theta} &= 90\degree - \theta + \frac{\theta}2 \\ &= 90\degree - \frac{\theta}2 \qed \end{align*}

Inverse trigonometric functions

Inverse trig functions sin1(x)\sin^{-1}(x), cos1(x)\cos^{-1}(x), tan1(x)\tan^{-1}(x) return the angle when you have the ratio xx. They are useful for missing angles.

Applications

definitions

The angle of elevation is the angle from horizontal up to some point of interest. The angle of depression is the angle from horizontal down to some point of interest.

strategies

  • Draw a diagram, label important points and given angles and sides (distances).
  • Light travels in a straight line.
  • Identify right angles.
  • Identify similar triangles.
  • Reuse variables when possible. For example if total distance is 1010, you can label part of it xx and the remaining 10x10 - x.
  • Verify your calculator is in degrees mode, when working with angles in degrees.